This post is all about the solution of the C. Sequence Master Codeforces Round 858 (Div. 2) Problem solution.

C. Sequence Master Codeforces Round 858 (Div. 2) Problem solution

Codeforces

Problem Statement :

YunQian considers an array q of 2m (possibly negative) integers good for some positive integer m if and only if the product of the m elements in the subsequence equals the sum of the m elements that are not in the subsequence for every possible subsequence of q that has length m. Formally, let U=1,2,...,2m. For all SU sets such that |S|=m, iSqi=iUSqi.

The distance between two arrays a and b, both of length k, is defined as i=1k|aibi|.

You are given a positive integer n and a 2-n integer array p.

Find the shortest distance between p and q across all good arrays q of length 2n. It can be shown for all positive integers n , at



Format of Input :

Timofey visited a well-known summer school and discovered a tree with n vertices. A tree is an undirected connected graph with no cycles.
Except for c0, every vertex in this tree is white. The vertex c0 is black in colour.
Timofey wishes to make all of the vertices of this tree black. He uses n1 operations to accomplish this. During the i-th operation, he selects the currently white vertex ci and paints it black.
Let us define tree positivity as the shortest distance between all pairs of different black vertices in it. The number of edges on the path from v to u is the distance between the vertices v and u.
Timofey wants to know the current state of affairs after each operation.

Format of the Output :

Output the shortest distance between p and a good q for each test case.



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